# How do you solve by completing the square x^2+4x-32=0?

${x}^{2} + 4 x = 32$
${x}^{2} + 4 x + 4 - 4 = 32$
${x}^{2} + 4 x + 4 = 32 + 4$
${\left(x + 2\right)}^{2} = 36$
$x + 2 = \pm \sqrt{36}$
$x = - 2 \pm 6$
${x}_{1} = - 8$
${x}_{2} = 4$