# How do you solve by completing the square: x^2+7x-5=0?

${x}^{2} + 7 x = 5$
${x}^{2} + 7 x + \frac{49}{4} - \frac{49}{4} = 5$
${\left(x + \frac{7}{2}\right)}^{2} = 5 + \frac{49}{4}$
${\left(x + \frac{7}{2}\right)}^{2} = \frac{69}{4}$
$x + \frac{7}{2} = \pm \sqrt{\frac{69}{4}}$
$x + \frac{7}{2} = \pm \frac{\sqrt{69}}{2}$
$x = - \frac{7}{2} \pm \frac{\sqrt{69}}{2}$