How do you solve c^2 = 111?

Jun 12, 2017

$\setminus \pm \setminus \sqrt{111}$

Explanation:

${c}^{2} = 111$
${c}^{2} - 111 = 0$
$\left(c + \setminus \sqrt{111}\right) \left(c - \setminus \sqrt{111}\right) = 0$
$c + \setminus \sqrt{111} = 0$
$c = - \setminus \sqrt{111}$
$c - \setminus \sqrt{111} = 0$
$c = \setminus \sqrt{111}$
$c = \setminus \pm \setminus \sqrt{111}$