# How do you solve (c+3)-2c-(1-3c)=2?

May 13, 2018

$c = 0$

#### Explanation:

1) Remove brackets as they are the same operation (addition / subtraction)

$c + 3 - 2 c - 1 - 3 c = 2$

2) Simplify the coefficient of c

$- 4 c + 3 - 1 = 2$

3) Simplify the number

$- 4 c + 2 = 2$

4) Subtract two from both sides

$- 4 c = 0$

5) Divide both sides by -4

$c = 0$