How do you solve #|c - 4| = 5#?

1 Answer
Dec 23, 2016

The solution is #c=9,-1#

Explanation:

#|c-4|=5#
To clear the absolute-value bars, I must split the equation into its two possible two cases, one case for each sign:

#(c-4)=5      -(c-4)=5#
or, #c=5+4     -c+4=5#
or, #c=9               c=4-5=-1#
Then the solution is #c=9,-1#