Question

How do you solve `cos(2x-pi/2)=1`?

Answer 1

`pi/4 + 2kpi`
`(5pi)/4 + 2kpi`

Explanation:

Trig unit circle -->
`cos (2x - pi/2) = 1`
There are 2 solution arcs:
a. `(2x - pi/2) = 0`
`2x = pi/2`
`x = pi/4`
b. `2x - pi/2 = 2pi`-->
`2x = 2pi + pi/2 = 5pi/2`
`x = (5pi)/4`
General answers:
`x = pi/4 + 2kpi`
`x = (5pi)/4 + 2kpi`