Question

How do you solve `cosx(6sinx - 5) = 0`?

Answer 1

`x = 0.99 , pi/2 , 2.15 , (3pi)/2`

Explanation:

cosx ( 6sinx - 5 ) = 0

hence cosx = 0 or 6sinx - 5 = 0 → `sinx = 5/6`

solve cosx = 0 `rArr x = pi/2 , (3pi)/2`

solve `sinx = 5/6 rArr x = 0.99 , x = (pi - 0.99) = 2.15`