How do you solve d/4+1>=-3?

Apr 29, 2017

$d \ge - 16$

Explanation:

multiply ALL terms by 4 to eliminate the fraction.

$\left(\cancel{4} \times \frac{d}{\cancel{4}}\right) + \left(4 \times 1\right) \ge \left(4 \times - 3\right)$

$\Rightarrow d + 4 \ge - 12$

$\text{subtract 4 from both sides}$

$\mathrm{dc} a n c e l \left(+ 4\right) \cancel{- 4} \ge - 12 - 4$

$\Rightarrow d \ge - 16 \text{ is the solution}$