Question

How do you solve `d- d + 2d + 1= 15`?

Answer 1

`d=7`

Explanation:

Starting off, we have more than one terms of `d` on the left hand side. So first, we collect like terms

`d-d+2d=2d`

Plugging back into the equation, getting rid of all the previous terms we just added we get

`2d+1=15`

As we want `d` on its own, we get rid of the extra constant of +1, and by doing this we do the opposite to both sides, which is to -1 from both sides, this cancels the +1 and you -1 from the other giving us

`2d=14`

As we want `d` not `2d` we divide by the value of how many `d's` we have, to give a value for `d`

`d=14/2`

As this can be made into an integer we put it into that, if not you can simplify the fraction if possible, if not leave it as the fraction before, or change it to a decimal.

`14/2=7`

`therefore` `d=7`