Question

How do you solve `e^(3r)+4=59`?

Answer 1

`r=ln55/3=1.336`

Explanation:

`e^(3r)+4=59` can be rewritten as `e^(3r)=59-4=55`

As "`ln`" is natural logarithm to the base `e`,

by taking logarithm of both sides to base `e`,

we get `" "3r=ln55` and

`r=ln55/3=4.00733/3=1.33578` or `1.336`

(using scientific calculator)