How do you solve $e^(3x)=4$ ?

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Answer 1 · 2018-03-27T13:10:52

$x=ln4/3~~0.46$

Given: $e^(3x)=4$

Take natural logarithm of both sides.

$ln(e^(3x))=ln4$

$3x=ln4$

Divide by $3$ .

$(color(red)cancelcolor(black)3x)/(color(red)cancelcolor(black)3)=ln4/3$

$x=ln4/3$

How do you solve e^(3x)=4e^(3x)=4?