How do you solve #e^(-5n-1)+3.9=75#? Precalculus Properties of Logarithmic Functions Natural Logs 1 Answer Noah G Aug 27, 2016 #e^(-5n - 1) = 75 - 3.9# #e^(-5n - 1) = 71.1# #-5n - 1 = ln71.1# #-5n = ln71.1 + 1# #n = -1.05# Hopefully this helps! Answer link Related questions What is the natural log of e? What is the natural log of 2? How do I do natural logs on a TI-83? How do I find the natural log of a fraction? What is the natural log of 1? What is the natural log of infinity? Can I find the natural log of a negative number? How do I find a natural log without a calculator? How do I find the natural log of a given number by using a calculator? How do I do natural logs on a TI-84? See all questions in Natural Logs Impact of this question 1207 views around the world You can reuse this answer Creative Commons License