Question

How do you solve `e^ { 6x - 1} = ( e ^ { 2} ) ^ { - x }`?

Answer 1

`x = 1/8`

Explanation:

If the basises are constant, then the exponents must be equal.

`exp (6x - 1) = exp (-2x)`

`6x - 1 = -2x`

`8x = 1`