Question

How do you solve `e^ { x - 1} = \frac { 1} { (e^4) )^ { x + 1}`?

Answer 1

`x=0`

Explanation:

Not quite sure of the notation here.

`e^(x-1)=(1/e^4)^(x+1)=(e^(-4)/1)^(x+1)`

`->e^(x-1)=e^(-4x-1)`

`->x-1=-4x-1=>x=0`