# How do you solve e^x-9xe^x=0?

Sep 1, 2015

Factor and solve each factor equal to $0$

#### Explanation:

${e}^{x} - 9 x {e}^{x} = 0$

${e}^{x} \left(1 - 9 x\right) = 0$

${e}^{x} = 0$ $\text{ }$ or $\text{ }$ $1 - 9 x = 0$

${e}^{x}$ is never $0$

$1 - 9 x = 0$ when $= = \frac{1}{9}$

The only solution is $\frac{1}{9}$