How do you solve #e^(x)-ln(x)=4#?

1 Answer
Nov 26, 2016

Answer:

#x=0.052546964867641 ....#
#x=1.47975688167648 ....#

graph{e^x-ln(x)-4 [-10, 10, -5, 5]}

Explanation:

There isn't a simple way to do this using only the properties of natural logarithms....

I'll put in the graph, but take a look at the comments below.