# How do you solve each system by elimination 2x+3y=9, x+5y=8?

Oct 25, 2016

$x = 3 , y = 1$

#### Explanation:

$2 x + 3 y = 9 \text{ and } x + 5 y = 8$

$x = 8 - 5 y$ is inserted in the first equation,

$2 \left(8 - 5 y\right) + 3 y = 9$ then remove the bracket:,

$16 - 10 y + 3 y = 9$, then simplify:

$- 7 y = - 7$, divide by $\left(- 7\right)$

gives $y = 1$

and $x = 8 - 5 = 3$