How do you solve # f(x)=x^2-x+3# using the quadratic formula?

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Answer 1 · 2017-07-19T11:25:19

See a solution process below:

For #f(x) = ax^2 + bx + c#, the values of #x# which are the solutions to the equation for #0# are given by:

#x = (-b +- sqrt(b^2 - 4ac))/(2a)#

Substituting #1# for #a#; #-1# for #b# and #3# for #c# gives:

#x = (-(-1) +- sqrt((-1)^2 - (4 * 1 * 3)))/(2 * 1)#

#x = (1 +- sqrt(1 - 12))/2#

#x = (1 +- sqrt(-11))/2#