# How do you solve  f(x)=x^2-x+3 using the quadratic formula?

Jul 19, 2017

See a solution process below:

#### Explanation:

For $f \left(x\right) = a {x}^{2} + b x + c$, the values of $x$ which are the solutions to the equation for $0$ are given by:

$x = \frac{- b \pm \sqrt{{b}^{2} - 4 a c}}{2 a}$

Substituting $1$ for $a$; $- 1$ for $b$ and $3$ for $c$ gives:

$x = \frac{- \left(- 1\right) \pm \sqrt{{\left(- 1\right)}^{2} - \left(4 \cdot 1 \cdot 3\right)}}{2 \cdot 1}$

$x = \frac{1 \pm \sqrt{1 - 12}}{2}$

$x = \frac{1 \pm \sqrt{- 11}}{2}$