How do you solve for all real values of x with the following equation 2 sin x + csc x = 3 ??

1 Answer
maganbhai P.
Feb 23, 2018

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Explanation:

#2sinx+cosecx=3#
#2sinx+1/sinx =3#
#2sin^2x+1=3sinx#
#2sin^2x-3sinx+1=0#
#2sin^2x-2sinx-sinx+1=0#
#2sinx(sinx-1)-1(sinx-1)=0#
#(2sinx-1)(sinx-1)=0#
#sinx=1/2# or #sinx=1#
#sinx=sin(pi/6)# or #sinx=sin(pi/2)#
So,
enter image source here

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