How do you solve for c in #a(b – c) = d#?

2 Answers
Mar 23, 2018

Answer:

#c=b-d/a#

Explanation:

Given: #a(b-c)=d#

Divide by #a# on both sides.

#(color(red)cancelcolor(black)a(b-c))/(color(red)cancelcolor(black)a)=d/a#

#b-c=d/a#

Subtract #b# from both sides.

#color(red)cancelcolor(black)b-color(red)cancelcolor(black)b-c=d/a-b#

#-c=d/a-b#

Reverse signs.

#:.c=-(d/a-b)#

#=b-d/a#

Mar 23, 2018

Answer:

#c=b-d/a#

Explanation:

#"divide both sides by a"#

#cancel(a)/cancel(a)(b-c)=d/a#

#rArrb-c=d/a#

#"subtract b from both sides"#

#cancel(b)-cancel(b)-c=d/a-b#

#rArr-c=d/a-b#

#"multiply all terms on both sides by "-1#

#rArrc=-d/a+b#

#rArrc=b-d/a#