How do you solve for #L# in #32LW=V#?

1 Answer
Mar 18, 2017

See the entire solution process below:

Explanation:

Divide each side of the equation by #color(red)(32)color(blue)(W)# to solve for #L# while keeping the equation balanced:

#(32LW)/(color(red)(32)color(blue)(W)) = V/(color(red)(32)color(blue)(W))#

#(color(red)(cancel(color(black)(32)))Lcolor(blue)(cancel(color(black)(W))))/(cancel(color(red)(32))cancel(color(blue)(W))) = V/(32W)#

#L = V/(32W)#