How do you solve for #r# : #q - 3r = 2# ?

1 Answer
Jim G.
May 21, 2018

#r=1/3(q-2)#

Explanation:

#"isolate the term in r"#

#"add "3r" to both sides"#

#qcancel(-3r)cancel(+3r)=2+3r#

#rArrq=3r+2#

#"subtract 2 from both sides"#

#rArrq-2=3r#

#"divide both sides by 3"#

#(q-2)/3=(cancel(3) r)/cancel(3)#

#rArrr=(q-2)/3=1/3(q-2)#

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