How do you solve for the voltages and currents in this circuit diagram?

1 Answer
Jun 26, 2016

Answer:

Please see below.

Explanation:

As #R_1# and #R_2# are in parallel, the resultant resistance #R# will be given by #1/(R_1)+1/(R_2)#.

Hence #1/R=1/3+1/6=1/2# and hence #R=2# #Omega#.

As the voltage of battery source is #120V#, assuming #0# internal resistance, current passing through circuit or #R_3# is #I_0=120/(15+2)=120/17=7 1/17# ampere.

and hence voltage #V_3# across it will be #120/17xx15=1800/17= 105 15/17V#

and that across other two resistances i.e. #V_1=V_2# will be #120-1800/17=240/17V# each.

Hence current #I-1# passing through #R_1# is #240/17xx1/3=80/17=4 12/17# ampere.

and current passing #I_2# through #R_2# is #240/17xx1/2=120/17=7 1/17# ampere.