# How do you solve for x given x-5>x+6 ?

Jan 21, 2015

The statement is false for every given $x \setminus \in \setminus R$.

Inutuitively, you're saying that if you pick a number and subtract 5, you get a greater number than adding 6 to the same number, which sounds quite strange indeed.

Using algebra, one gets $x - 5 > x + 6 \setminus \iff x - x > 5 + 6 \setminus \iff 0 > 11$
which is of course false.