Question

How do you solve for x in `2x + 3y = 6`?

Answer 1

See a solution process below:

Explanation:

First, subtract `color(red)(3y)` from each side of the equation to isolate the `x` term while keeping the equation balanced:

`2x + 3y - color(red)(3y) = 6 - color(red)(3y)`

`2x + 0 = 6 - 3y`

`2x = 6 - 3y`

Now, divide each side of the equation by `color(red)(2)` to solve for `x` while keeping the equation balanced:

`(2x)/color(red)(2) = (6 - 3y)/color(red)(2)`

`(color(red)(cancel(color(black)(2)))x)/cancel(color(red)(2)) = (6 - 3y)/2`

`x = (6 - 3y)/2`

Or

`x = 6/2 - (3y)/2`

`x = 3 - 3/2y`