How do you solve for x in #-[3(2x-1)+x]=2[x-2(5x+4)]#?

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Answer 1 · 2016-06-15T08:41:38

# x = -19/11#

#-[3(2x-1)+x]=2[x-2(5x+4)]#

Start inside the square brackets and simplify.

#-[6x-3+x] = 2[x-10x-8]#

#" "-[7x -3] = 2[-9x -8]#

Now multiply out the square brackets:
#" "-7x + 3 = -18x -16]#

#" " 18x -7x = -16-3#

#" "11x = -19#

# x = -19/11#