# How do you solve for x in -[3(2x-1)+x]=2[x-2(5x+4)]?

Jun 15, 2016

$x = - \frac{19}{11}$

#### Explanation:

$- \left[3 \left(2 x - 1\right) + x\right] = 2 \left[x - 2 \left(5 x + 4\right)\right]$

Start inside the square brackets and simplify.

$- \left[6 x - 3 + x\right] = 2 \left[x - 10 x - 8\right]$

$\text{ } - \left[7 x - 3\right] = 2 \left[- 9 x - 8\right]$

Now multiply out the square brackets:
" "-7x + 3 = -18x -16]

$\text{ } 18 x - 7 x = - 16 - 3$

$\text{ } 11 x = - 19$

$x = - \frac{19}{11}$