# How do you solve for x in 3(x-1) = 2 (x+3)?

Sep 28, 2014

3 (x-1) = 2 (x + 3)

3.x + 3 (-1) = 2.x + 2.3

$3 x + \left(- 3\right) = 2 x + 6$

$3 x - 3 = 2 x + 6$

for combining like terms either you can subtract $2 x$ from the Left Hand Side ( LHS) or subtract $3 x$ from the Right Hand Side ( RHS).

$3 x - 3 - 3 x = 2 x + 6 - 3 x$

$- 3 = - x + 6$

subtracting $6$ from both sides;

$- 3 - 6 = - x + 6 - 6$

$- 9 = - x$

$x = 9$