Question

How do you solve for x in `ax+b=cx-d`?

Answer 1

`x = (b +d) / (c-a)`

Explanation:

`color(blue)(ax) +b = color(blue)(cx)-d`

`b +d = color(blue)(cx-ax`

`b +d = x color(blue)((c-a))`

`x = (b +d) / (c-a)`