How do you solve for x in #ax = bx -c#?

2 Answers
Jul 27, 2018

Answer:

#x=-c/(a-b)#

Explanation:

#"Collect terms in x on the left side "#

#"subtract "bx" from both sides"#

#ax-bx=-c#

#"take out a "color(blue)"common factor "x#

#x(a-b)=-c#

#"divide both sides by "a-b#

#x=-c/(a-b)#

Jul 28, 2018

Answer:

#x=-c/(a-b)#

Explanation:

If we want to solve for #x#, we can first get all of our #x# terms on one side. This can easily be done by subtracting #bx# from both sides.

We now have

#ax-bx=-c#

Since both terms on the left have an #x# in common, we can factor that out to get

#x(a-b)=-c#

Lastly, we can divide both sides by #a-b# to get

#x=-c/(a-b)#

Hope this helps!