# How do you solve for y in  -12x = 3(y - 3)?

Sep 21, 2015

$y = - 4 x + 3$

#### Explanation:

Expand $3 \left(y - 3\right)$ first.
$- 12 x = 3 \left(y - 3\right)$
$- 12 x = 3 y - 9$

Now, you can work on isolating $y$.
$- 12 x = 3 y - 9$
$- 12 x + 9 = 3 y$

Multiply both sides by 1/3 so we can cancel the coefficient of $y$.
$\left(\frac{1}{3}\right) \left(- 12 x + 9\right) = \left(\frac{1}{3}\right) \left(3 y\right)$
$- 4 x + 3 = y$

$y = - 4 x + 3$.