How do you solve #\frac { 1} { 3} ( g - 3) = 9#?

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Answer 1 · 2018-01-20T22:56:09

See a solution process below:

First, multiply each side of the equation by #color(red)(3)# to eliminate the need for parenthesis while keeping the equation balanced:

#color(red)(3) xx 1/3(g - 3) = color(red)(3) xx 9#

#color(red)(3)/3(g - 3) = 27#

#1(g - 3) = 27#

#g - 3 = 27#

Now, add #color(red)(3)# to each side of the equation to solve for #g# while keeping the equation balanced:

#g - 3 + color(red)(3) = 27 + color(red)(3)#

#g - 0 = 30#

#g = 30#