# How do you solve \frac { 1} { 3} x + 2= 16?

Jul 16, 2017

See a solution process below:

#### Explanation:

Step 1) Subtract $\textcolor{red}{2}$ from each side of the equation to isolate the $x$ term while keeping the equation balanced:

$\frac{1}{3} x + 2 - \textcolor{red}{2} = 16 - \textcolor{red}{2}$

$\frac{1}{3} x + 0 = 14$

$\frac{1}{3} x = 14$

Step 2) Multiply each side of the equation by $\textcolor{red}{3}$ to solve for $x$ while keeping the equation balanced:

$\textcolor{red}{3} \times \frac{1}{3} x = \textcolor{red}{3} \times 14$

$\cancel{\textcolor{red}{3}} \times \frac{1}{\textcolor{red}{\cancel{\textcolor{b l a c k}{3}}}} x = 42$

$x = 42$