How do you solve #\frac { - 1} { 5k ^ { 2} + 2k } - \frac { 6} { 5k + 2} = \frac { 6} { 5k ^ { 2} + 2k }#?

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Answer 1 · 2018-07-18T09:19:18

#=>k=-7/6#

Here ,

#-1/(5k^2+2k)-6/(5k+2)=6/(5k^2+2k#

#=>-{1/(k(5k+2))+6/(5k+2)}=6/(k(5k+2))#

#=>1/(k(5k+2))+6/(5k+2)=-6/(k(5k+2))#

Multiplying each term of eqn. by #k(5k+2)!=0# , we get

#=>1+6k=-6#

#=>6k=-1-6=-7#

#=>k=-7/6#