Question

How do you solve `\frac { 1} { 9} ( 4n + 33) = \frac { 1} { 3} ( 2n + 5)`?

Answer 1

`n=9`

Explanation:

`1/9 (4n+33)=1/3 (2n+5)`
Multiply both side by 9
`4n+33=3(2n+5)=6n+15`
`33-15=6n-4n`
`2n=18`
`n=9`