How do you solve #-\frac { 2} { 3} x = \frac { 4} { 3}#?

2 Answers
smendyka
Feb 1, 2018

See a solution process below:

Explanation:

Multiply each side of the equation by #color(red)(3)/color(blue)(-2)# to solve for #x# while keeping the equation balanced:

#color(red)(3)/color(blue)(-2) xx (-2)/3x = color(red)(3)/color(blue)(-2) xx 4/3#

#cancel(color(red)(3))/cancel(color(blue)(-2)) xx color(blue)(cancel(color(black)(-2)))/color(red)(cancel(color(black)(3)))x = cancel(color(red)(3))/color(blue)(-2) xx 4/color(red)(cancel(color(black)(3)))#

#x = 4/color(blue)(-2)#

#x = -2#

Jim G.
Feb 1, 2018

#x=-2#

Explanation:

#"note that "2/3x=(2x)/3#

#rArr-(2x)/3=4/3#

#"since the fractions are equal and have a denominator of 3"#

#"then the numerators will be equal"#

#rArr-2x=4#

#"divide both sides by "-2#

#(cancel(-2) x)/cancel(-2)=4/(-2)#

#rArrx=-2#

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