How do you solve #\frac { 2m + 3} { m } = 1#?

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Answer 1 · 2018-04-23T01:08:29

#m = -3#

Multiply both sides of the equation by m and cancel where possible.

#cancel(m)*(2*m + 3)/cancel(m) = m*1#

This exercise yields the result

#(2*m + 3)/1 = m*1#

And that simplifies into the equation

#2*m + 3 = m#

Solving for m

#2*m - m = -3#

#(2-1)*m = -3#

#m = -3#

I hope this helps,
Steve