How do you solve #\frac { | 2x - 1| } { 3} < 3#?

1 Answer
Apr 26, 2018

#-4< x<5#

Explanation:

Multiply both values by 3 to get #abs(2x-1)<9#

Since doing #abs()# takes the positive of the function, what is inside can be both positive or negative.

So, we have:
#2x-1<9# or #-2x+1<9#

#2x<10# or #2x>-8#

#x<5# or #x> -4#

#-4< x<5#