How do you solve #\frac { 30} { x } + 10= 5#?

1 Answer
Jul 18, 2017

See a solution process below:

Explanation:

First, subtract #color(red)(10)# from each side of the equation to isolate the #x# term:

#30/x + 10 - color(red)(10) = 5 - color(red)(10)#

#30/x + 0 = -5#

#30/x = -5#

Next, multiply each side of the equation by #color(red)(x)# to eliminate the fraction while keeping the equation balanced:

#30/x xx color(red)(x) = -5 xx color(red)(x)#

#30/color(red)(cancel(color(black)(x))) xx cancel(color(red)(x)) = -5x#

#30 = -5x#

Now, divide each side of the equation by #color(red)(-5)# to solve for #x# while keeping the equation balanced:

#30/color(red)(-5) = (-5x)/color(red)(-5)#

#-6 = (color(red)(cancel(color(black)(-5)))x)/cancel(color(red)(-5))#

#-6 = x#

#x = -6#