How do you solve #\frac { 3r + 12} { 9} = \frac { 2r - 1} { 5}#?

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Answer 1 · 2016-11-16T02:45:09

#r=23#

#(3r+12)/9=(2r-1)/5#

Multiply both sides by #45#.

#45xx(3r+12)/9=45xx(2r-1)/5#

#5cancel(45)xx(3r+12)/cancel9=9cancel(45)xx(2r-1)/cancel5#

#5(3r+12)=9(2r-1)#

Open the brackets and simplify.

#15r+60=18r-9#

Add #9# to both sides.

#15r+69=18r#

Subtract #15r# from both sides.

#69=3r#

Divide both sides by #3#.

#23=r# or #r=23#