How do you solve #-\frac { 4} { y - 4} = 3#?

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Answer 1 · 2017-08-01T22:27:56

#y = 8/3#

Given: #-4/(y-4) = 3#

Get rid of the fraction by multiplying both sides of the equation by the denominator #y - 4)#:

#-4/cancel(y-4) *cancel (y-4)/1= 3(y-4)#

#-4 = 3(y - 4)#

Distribute on the right side of the equation:

#-4 = 3y - 12#

Add #12# to both sides to isolate the variable:

#-4 + 12 = 3y -12 + 12#

#8 = 3y#

Divide both sides by #3#L

#8/3 = (cancel(3)y)/cancel(3)#

#y = 8/3#

CHECK ANSWER:

#-4/(8/3-4) = 3#

#-4/(8/3-12/3) = 3#

#-4/(-4/3)= 3#

Change division to multiplication by multiplying by the reciprocal of the denominator:

#-cancel(4) * -3/(cancel(4)) = 3#