How do you solve #\frac { 6x + 3} { 7} = - 3#?

1 Answer
Oct 10, 2017

See a solution process below:

Explanation:

First, multiply each side of the equation by #color(red)(7)# to eliminate the fraction while keeping the equation balanced:

#color(red)(7) xx (6x + 3)/7 = color(red)(7) xx -3#

#cancel(color(red)(7)) xx (6x + 3)/color(red)(cancel(color(black)(7))) = -21#

#6x + 3 = -21#

Next, subtract #color(red)(3)# from each side of the equation to isolate the #x# term while keeping the equation balanced:

#6x + 3 - color(red)(3) = -21 - color(red)(3)#

#6x + 0 = -24#

#6x = -24#

Now, divide #color(red)(6)# from each side of the equation to solve for #x# while keeping the equation balanced:

#(6x)/color(red)(6) = -24/color(red)(6)#

#(color(red)(cancel(color(black)(6)))x)/cancel(color(red)(6)) = -4#

#x = -4#