How do you solve #\frac { x ^ { 2} } { 8} - 4= \frac { x } { 2}#?
1 Answer
May 2, 2018
Explanation:
#"multiply all terms by 8 to eliminate fractions"#
#cancel(8)xx x^2/cancel(8)-(8xx4)=cancel(8)^4xx x/cancel(2)^1#
#rArrx^2-32=4x#
#"subtract "4x" from both sides"#
#x^2-4x-32=0larrcolor(blue)"in standard form"#
#"the factors of - 32 which sum to - 4 are - 8 and + 4"#
#rArr(x-8)(x+4)=0#
#"equate each factor to zero and solve for x"#
#x+4=0rArrx=-4#
#x-8=0rArrx=8#
