# How do you solve #\frac{- x - 3}{x + 2} \leq 0#?

##### 2 Answers

HI

given equation,

**thus ,to solve this question we need to get the denominator term #(x+2)# in numerator,**

thus

=

=

now,

getting minus sign common,

from first term,

=

=-1

as this term is less than and equal to zero

hence,

-1<=

now,getting (x+2) to the numerator side to left and minus one to right

**And x cannot be equal to -2 as at x=-2 the given equation is not defied as denominator is 0**

thus ,x can be greater than -2 upto positive infinity

**Solution :** **in interval notation**

#### Explanation:

Crirical points are

Crirical points are

Sign change:

Interval ----------- Sign of

When

When

When

When

Solution :

graph{(-x-3)/(x+2) [-11.25, 11.25, -5.625, 5.62]} [Ans]