# How do you solve \frac{y + 4}{7} = 3?

$y + 4 = 3 \cdot 7$
$y + 4 = 21$
$y = 21 - 4$
$y = 17$
$\frac{17 + 4}{7} = 3$
$\frac{21}{7} = 3$
$3 = 3$