How do you solve #\frac { z} { - 2} - 6\leq - 2#?

1 Answer
Nov 29, 2017

See a solution process below:

Explanation:

First, add #color(red)(6)# to each side of the inequality to isolate the #z# term while keeping the inequality balanced:

#z/-2 - 6 + color(red)(6) <= -2 + color(red)(6)#

#z/-2 - 0 <= 4#

#z/-2 <= 4#

Now, multiply each side of the inequality by #color(blue)(-2)# to solve for #z# while keeping the inequality balanced. However, because we are multiplying or dividing an inequality by a negative number we must reverse the inequality operator:

#color(blue)(-2) xx z/-2 color(red)(>=) color(blue)(-2) xx 4#

#cancel(color(blue)(-2)) xx z/color(blue)(cancel(color(black)(-2))) color(red)(>=) -8#

#z >= -8#