# How do you solve h^ { 2} - 2h - 0= 3?

May 15, 2017

$h = 3 , - 1$

#### Explanation:

${h}^{2} - 2 h - 0 = 3$

minus 3 to both sides,

${h}^{2} - 2 h - 3 = 0$

use a quadratic formulae to solve where,
$a = 1 , b = - 2 \mathmr{and} c = - 3$

$h = \frac{- b \pm \sqrt{{b}^{2} - 4 a c}}{2 a}$

$h = \frac{- \left(- 2\right) \pm \sqrt{\left(- {2}^{2}\right) - 4 \left(1\right) \left(- 3\right)}}{2 \left(1\right)}$

$h = \frac{2 \pm \sqrt{4 + 12}}{2}$

$h = \frac{2 \pm \sqrt{16}}{2} = \frac{2 \pm 4}{2}$

$h = \frac{2 + 4}{2} , \frac{2 - 4}{2}$

$h = 3 , - 1$