# How do you solve ln e^(-2x) = 8?

Feb 19, 2016

I found: $x = - 4$

#### Explanation:

We can first take the $- 2 x$ and place it in front of the log:

$- 2 x \ln e = 8$

then remember that: $\ln e = 1$
and write:

$- 2 x = 8$
so that $x = - \frac{8}{2} = - 4$