# How do you solve k+ 1= 3k - 1?

May 9, 2018

$k = 1$

#### Explanation:

As per the question, we have

$k + 1 = 3 k - 1$

$\therefore 1 + 1 = 3 k - k$

$\therefore 2 k = 2$

$\therefore k = \frac{2}{2}$

$\therefore k = 1$

$\therefore k = 1$ is the solution to this problem.

May 9, 2018

$k = 1$

#### Explanation:

$k + 1 = 3 k - 1$

Subtract 1k from each side, remember what you do on one side you do on the other.
$1 = 2 k - 1$

$2 = 2 k$
$2 k = 2$
$\frac{2 k}{2} = \frac{2}{2}$
$\frac{2}{2}$ is the same thing as $\frac{1}{1}$ which is equal to one:
$k = 1$