# How do you solve #k^ { 2} - 3k - 88= 0#?

##### 2 Answers

and

#### Explanation:

Factor

Set each pair equal (

(k-11) x ( k+8) Break the trinomial into two binomials and solve for k

k = + 11 k = -8

#### Explanation:

The C value in the trinomial

The B value in the the trinomial is negative this means that the negative factor of 88 must be larger than the positive factor by 3

There are several factor combinations for 88 : 1 x 88, 2 x 44 , 4 x 22 and 8 x 11. 8 x 11 has a difference of three.

So 11 must be negative since it is larger and 8 must be positive

k = -8 and + 11