# How do you solve K_2PtCl_4 + NH_3 -> Pt(NH_3)_2Cl_2 + KCl?

Jun 25, 2018

${K}_{2} P t C {l}_{4}$ $+ 2$ $N {H}_{3}$ $\to$ $P t {\left(N {H}_{3}\right)}_{2} C {l}_{2}$ $+ 2$ $K C l$

#### Explanation:

Start by counting the atoms on both sides of the equation:

L - Atom - R
2 - K - 1
1 - Pt - 1
4 - Cl - 3
1 - N - 2
3 - H - 6

Upon inspection, looks like only Pt is balanced on both sides ( L eft and R ight).

Start by placing a 2 in front of $K C l$ since there are 2 K on the left, but only 1 K on the right. Doing so will balance out K and Cl.

Next, place a 2 in front of $N {H}_{3}$ since there is 1 N on the left and 2 N on the right & 3 H on left and 6 H on right. Doing so will balance out N and H.

These 2 steps will balance the entire equation:
${K}_{2} P t C {l}_{4}$ $+ 2$ $N {H}_{3}$ $\to$ $P t {\left(N {H}_{3}\right)}_{2} C {l}_{2}$ $+ 2$ $K C l$